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A homeowner wishes to insulate her attic with fiberglass insulation to
conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between
the rafters in the attic. If the roof is 6 m from peak to eave and the attic space
is 2 m high at the peak, how long does each of the pieces of insulation need to be?
Round to the nearest tenth.


16. Geometry. For the home described in exercise 15, if the roof is 7 m from peak to
eave and the attic space is 3 m high at the peak, how long does each of the pieces
of insulation need to be? Round to the nearest tenth.

2007-02-22 03:47:10 · 1 answers · asked by Anonymous in Science & Mathematics Engineering

1 answers

First, let's get the space checked. It seems to be a 6 m by 2 m deal. 40 cm is 0.4 m
To have 2 m covered, you need 5 pieces of the fiberglass insulation. Each piece has to be 6 m long.

For the second part, calculate the space again. 7 m by 3 m. You can have 3 divided by 0.4, which is almost 7.5. Then have the rolls be 7 m long each.
So, you will need 7.5 rolls of 7 m of length.

2007-02-22 04:09:20 · answer #1 · answered by F B 3 · 0 0

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