How can the pump equation be affected by efficiency?

Answer 1

This equation (ref.),

P = Q*H*S/(3960*mu), where
P = Power, hp
Q = Flow Rate, gpm
S = Specific Gravity of fluid
H = Head height, ft
mu = Efficiency coefficient

gives the mechanical power needed to drive a pump delivering the given flow rate and head for a liquid of the given specific gravity. Clearly required power is inversely proportional to efficiency mu.

Answer 2

Elements as matter, gases and liquid (in various states) all exist as variables in the equation, affecting performance.

Performance is affected by efficiency and effectivity. Efficiency has to do with performance against a standard. All the variables that affect the standard measure must be monitored against the actual measure to determine how efficiency is being impacted. Otherwise the variation in performance is not determinable nor is it correctible.

Observance of the effect of the elements may be evidential in terms of the impact on the volume related to temperature, pressure and viscosity. These are some measurements.

Efficiency is usually measured in terms of hours and rate, a measure of time and motion at standard and at actual.

Effectivity is putting this into a cost vs. benefit based equation, that places a value on performance. Every performance is measured in terms of an expected value vs. an actual value returned from the event within a certain period.

Benefits/cost (KPI) X efficiency = effectivity
KPI divided by effectivity = growth
rate of growth can be used to determine the return on the investment in a new pump or replacement, if put on an annualized basis.