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6 answers

it is achieved by 15 reds each followed by fifteen blacks followed by yellow.brown.green blue pink black total 36

2007-02-21 04:59:38 · answer #1 · answered by minty359 6 · 0 0

36

2007-02-21 19:32:56 · answer #2 · answered by the bop 1 · 0 0

36

2007-02-21 13:18:59 · answer #3 · answered by Anonymous · 0 0

It is 36, there are no other options unless you cheat. 155 is the highest possible break with a free ball red to start. I have heard of a 152 being made.

2007-02-21 13:10:26 · answer #4 · answered by G C 4 · 0 0

15 reds, 15 blacks, then all the colours - 6 - so the answer is 36. but the it´s not the highest break thou.........

2007-02-21 13:24:24 · answer #5 · answered by Archie R 2 · 0 0

every red with the black and all the colours...

there is no minimum or maximum ball count there's only one way of doing it!!!

2007-02-21 12:56:32 · answer #6 · answered by lion of judah 5 · 0 0

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