can someone clever tell the formula ( & explain in layman terms ) the formula for the following calculation
the current in a coil changes from 5a to 2a in 0.05s & induces a voltage of 30v in the coil, what is the inductance of the coil
my brain has ceased
please help
2007-02-19 07:26:50 · 2 answers · asked by R I P 2 in Science & Mathematics ➔ Engineering
A circuit has an inductance of 1 henry if 1 volt is induced in the circuit when the current changes at the rate of 1 amp per second.
so H=volts/ i2-i1/ t
rate of increase in current = (2-5)/0.005 =-60 amps / sec
inductance = 30v divided by 60a/s= 0.5henerys
inductance of coil = 0.5H
swimmered7 has got it wrong 1 H = Vs divided by Amps per sec
2007-02-19 10:52:23 · answer #1 · answered by mad_jim 3 · 0⤊ 0⤋
When the current in a coil changes with time, an emf is induced in the coil according to Faraday's law. The self-induced emf is:
E = -L (dI/dt) where L is the inductance of the coil.
So, as helpful as the above sentence is, the SI unit of inductance is henry (H), which equals 1 volt-second per ampere.
1 H = 1 (Vs/A)
You have A= 5 - 2 = 3 and Vs= (30)(0.05)= 15
Therefore, H= 15/3=5
The inductance of your coil is 5 H.
2007-02-19 15:45:48 · answer #2 · answered by swimmerd76 2 · 2⤊ 0⤋