grab the chicken first, drop it off.. garb the fox, when you get across, drop off the fox, grab the chicken back.. drop the chicken back off, grab the feed.. drop the feed off, turn back and grab the chicken.. the end..
2007-02-17 22:37:53
·
answer #1
·
answered by pitbullcopper2004 5
·
0⤊
0⤋
Feed the bag of seed to the chicken, feed the chicken to the fox, transport the fox across the river in the raft.
2007-02-22 04:48:27
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
Beats me:
Lemme guess!:
The chicken eats all the seed. The wolf eats the chicken!
Awkward right?
or let's do the practical way...
1. Bring the chicken to the other side
2. Return for the fox and get the fox. Make sure you bring the chicken back so that the fox won't eat him.
3. Get the feed and bring it to the other side.
4. Go back and get the chicken!
Just to make sure: Don't let the fox eat the feed!
2007-02-18 07:32:37
·
answer #3
·
answered by -.::Bianca Jacinto::.- 2
·
0⤊
0⤋
Take the chicken over first
return for the fox
Drop the fox off and bring the chicken back
leave he chicken on the other side and bring the feed and leave it with the fox
Go back an get the chcken
2007-02-18 06:42:41
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
I would just put a muzzle on the mouth of the chicken & fox, then I would glue the seed, chicken, and fox all together.
This would make one item, which I could then, safely bring across.
2007-02-18 07:00:20
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
i've heard this before but i forgot how to do it.you should include the consequences,say if you move the fox and leave the chicken and a bag of seed the chicken would eat the seed, something like that.
2007-02-18 06:41:10
·
answer #6
·
answered by warrior is a child 6
·
0⤊
0⤋
Kill the fox, eat the chicken and forget the seed. allot less rowing that way!!!!!!
2007-02-18 06:59:17
·
answer #7
·
answered by slayton59 2
·
1⤊
0⤋
I've know of this brainteaser years ago... the answer is which most of them got it already.
2007-02-18 08:42:02
·
answer #8
·
answered by Cherry Shortcake 3
·
0⤊
0⤋