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Well i want to huck up my TV to my computer but it uses composit video and i have an S-video port on you computers so i found this simple scematic
http://www.tkk.fi/Misc/Electronics/circuits/svideo2cvideo.html
It uses one 10v or more 470 pF (ceramic) capacitor. But i cant find one on radioshacks site (i was just going to go pick one up) But they did have a 0.0047µF (ceramic) capacitor.

And since i dont know the value difrence betwen pF and µF i tought it might be th same.

I have a hole contaner of capaciters down in my shop, Is ther a way to find out there values using a voltometer.

2007-02-17 06:50:40 · 0 answers · asked by Tim Sing 1 in Science & Mathematics Engineering

0 answers

The difference between the 2 units is 1 million, so you need to shift 6 places. So 470 pF is equal to 0.00047µF. One thing I never understood is why there is no unit called a fempto-Farad. If that were the case, then you could have .47 fF.

Capacitors cannot be measured like resistors, so no multimeter will help you. You would need a more expensive instrument called a capacitor tester. Now, if you need to add capacitances, you would connect capacitors in parallel (unlike resistors which go in series).

2007-02-17 07:01:39 · answer #1 · answered by Anonymous · 1 0

470 Pf Capacitor

2016-10-31 07:03:37 · answer #2 · answered by ? 4 · 0 0

Ceramic capacitors don't get anywhere near as large as 470uf. I'm not sure what cereal box JohnM read, but 470 microfarad is a very common electrolytic size. They go as small as .1uf. Like everyone else said, you need to know the right value first. Ohms ain't for capacitors.

2016-03-13 01:11:33 · answer #3 · answered by Anonymous · 0 0

For the best answers, search on this site https://shorturl.im/awLOV

Sounds like you are reading the value of the ceramic capacitor incorrectly. Capacitors are measured in Farads or microFarads not in ohms. Without seeing the circuit it's not really feasable to advise you what you could replace the ceramic capcitor with although you seemed to have proven that the electrolytic you have is not the answer and at very least the incorrect value. .

2016-04-06 17:09:47 · answer #4 · answered by Anonymous · 0 0

A capacitor is a passive electronic component that stores energy in the form of an electrostatic field. In its simplest form, a capacitor consists of two conducting plates separated by an insulating material called the dielectric. The capacitance is directly proportional to the surface areas of the plates, and is inversely proportional to the separation between the plates. Capacitance also depends on the dielectric constant of the substance separating the plates.

The standard unit of capacitance is the farad, abbreviated F. This is a large unit; more common units are the microfarad, abbreviated µF (1 µF = 10-6 F) and the picofarad, abbreviated pF (1 pF = 10-12 F).

Capacitors can be fabricated onto integrated circuit (IC) chips. They are commonly used in conjunction with transistors in dynamic random access memory (DRAM). The capacitors help maintain the contents of memory. Because of their tiny physical size, these components have low capacitance. They must be recharged thousands of times per second or the DRAM will lose its data.

Large capacitors are used in the power supplies of electronic equipment of all types, including computers and their peripherals. In these systems, the capacitors smooth out the rectified utility AC, providing pure, battery-like DC.
capacitor

2007-02-17 07:17:20 · answer #5 · answered by danny c 1 · 2 0

470 picofarad = 0.00047 microfarad

2007-02-17 07:02:46 · answer #6 · answered by Zlavzilla 3 · 1 0

I believe you are off by a tenth. 470pF = 0.00047µF

2007-02-17 06:59:03 · answer #7 · answered by Anonymous · 1 0

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