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There is a twenty inches box which can be switched on the electric power supply. It can "work" for any time, it consumes much more energy (electric supply) than all of the losses (friction, radiation, vibration etc.) It does not store the energy, you can retrieve only a small amount. I really want to know weather it infringe the law of E.C. or comply - and I miss. I guess this "box" transforms the energy into an unknown form otherwise it could eliminate the whole energy of the universe -theoretically during a very long time period. If I get serious answers I will put it (pictures and some comments of it's principle -which is really simply) up to the net in some days.

2007-02-16 08:16:42 · 2 answers · asked by Miklós G 1 in Science & Mathematics Engineering

2 answers

Yes this would violate the Energy Conservation Law.

When you say it can consume/transform much more energy than you are feeding it can you give an estimate for how much more and what forms the energy in and outs are that you have measured.

Is it 10 times the energy introduced or 100 times. Your explaination leaves out most of the details needed to evaluate it. The pictures would be interesting, but some more details would probly make it possible to show a measuring error, or a missed energy out.
There are a number of possible places you may have gone off track here. Because you state that the device can be operated for long periods without noticible heat gain I would focus on the measurement of the electricity.

if using the breaker to determine how much energy this is drawing this could be off by 20% due to a number of things

if using a multimeter, what is it's accuracy and are you testing that you are not feeding in AC, and feeding back DC or AC that your meter is not reporting? Digital meters can give erronious readings in some circumstances.

2007-02-16 08:47:05 · answer #1 · answered by oneirondreamer 3 · 0 0

If the box actually exists, you are adding wrong. Did you account for losses in power supply itself? I doubt it converts energy to an 'unknown' form, but I bet it converts it to a form you are not measuring properly.

2007-02-16 19:40:23 · answer #2 · answered by STEVEN F 7 · 0 0

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