Shannon's formula?

Question

if the (s/n) = 15 for a given channel, what is the channel capasity if the bandwdth = 10 KHZ?

Answer 1

Shannon's Formula c = b log2 (1 + s)
for example

signal to noise ratio 127
b = 3000 b = bandwidth
as shannon's formula states to add one to the signal to noise ratio to make it 128

Log 2 = 27= 128

then we multiply the log2 by the bandwidth to get

21000 Bps

C=BXL
in formula the answer:
21000 = 3000 x log2
{the log of 128 to the base 2 is 7
multiplication of that 7 by 3000 to give the answer 21000.}

Answer 2

So according to formula given before your channel capacity is 10000*log(2)(16) = 40000 b/sec = 40 kb/sec. This is the maximum bit rate over this channel for this s/n ratio.

Answer 3

The question has been asnwered but it's actyually called the Shannon-Hartley Law.