Please help! I really need help on this! The directions for this problem is to factor it.
(9p - 3pq) + (2nq - 6n)
You really don't know how much I have really tried. You also don't know how much I would appreciate any help I can get! Thank you so much to anyone that contributes in helping me with this!
2007-02-15 17:11:41 · 3 answers · asked by miss pochacco 3 in Education & Reference ➔ Other - Education
(9p - 3pq) + (2nq - 6n) <
2007-02-15 17:21:29
·
answer #1
·
answered by BB 3
·
0⤊
0⤋
= 3p(3 - q) + 2n(q - 3) << factor out -1 which reverses order of (q-3)
= 3p(3 - q) - 2n(3 - q) << now you can factor out (3-q)
= (3p - 2n)(3 - q) <
Rewrite the second expression as -(6n-2nq.)
For the first expression, the common term is 3p, and that for the second it is -2n. Hence the given expressions are rewritten as
3p(3-q)-2n(3-q). As 3-q is common, this is written as
(3-q)(3p-2n) which is the answer.
2007-02-16 08:21:11 · answer #2 · answered by greenhorn 7 · 0⤊ 0⤋
Take 3p out of the left side and 2n out of the right side.
2007-02-16 01:16:25 · answer #3 · answered by TheMatador 2 · 0⤊ 0⤋