Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
2 hours
4 ½ hours
5 ¾ hours
6 hours
7 ½ hours
2007-02-15 10:59:42 · 3 answers · asked by Anonymous in Sports ➔ Cycling
okay without really doing too much math. In the first 3 hours where the first guy is going 6mph. The guy goes 18 miles. Then the second guy starts and you can just think that he is going 4 mph faster so he need to catch up 18 miles at a rate of 4 mph, so just divide 18 by 4 and you will know how long it takes. Thats just the wordy way of doing it, i hope that helps.
2007-02-15 19:16:37 · answer #1 · answered by markit87 2 · 0⤊ 0⤋
maybe the second cyclist ate a clif shot. ;)
seriously, distance= rate * time. you need to give the first cyclist the 3 hour handicap (6mph*3 hours=18 miles).
2007-02-15 20:05:00 · answer #2 · answered by borracho111 4 · 0⤊ 0⤋
Rider one..........................................Rider two
6mphx3 + 6mph x ?..............10mph x ?
18+6x?=10x?
18=4x?
4,5=?
At this speed please don't call them cyclists (bike riders maybe)
Joggers go faster than this
2007-02-15 23:03:33 · answer #3 · answered by Glenn B 7 · 0⤊ 0⤋