Find the output voltage for the circuit show here
http://img.photobucket.com/albums/v638/ravenatic20/output.jpg
Explain your answer, and show your work. Thanks and good luck :)
2007-02-15 10:03:52 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Ok, you have a simple series circuit composed of a 10VDC source in series with a 100K and 50K resistor, with your output being taken from the 50K resistor. This is a voltage divider problem.
Vs = 10V
R1 = 100K
R2 = 50K
Vout = VR2
So,
VR2 = Vs(R2/(R1 + R2)) = 10V(50K/(100K + 50K) = 3.33V
Another way you could figure this out would be to find current first, then solve VR2 in terms of V = I * R.
Vs = 10V
R1 = 100K
R2 = 50K
Vout = VR2
I = V/(R1 + R2) = 10V(100K + 50K) = 66.67uA
VR2 = I * R2 = 66.67uA * 50K = 3.33V
2007-02-15 23:37:38 · answer #1 · answered by joshnya68 4 · 0⤊ 0⤋
Agree, learn for yourself but here's a hint, The resitors in the circuit only impede the current flow. Its a trick question.
2007-02-15 12:21:41 · answer #2 · answered by mhog68 1 · 0⤊ 0⤋
a million. offset...IC would desire to have been broken or instructions on connection given in instruction manual no longer accompanied. 2. Heavy noise....floor would desire to be open or ( if severe i/p type) "look after ring" and protective no longer presented.
2016-10-02 05:08:59 · answer #3 · answered by ? 4 · 0⤊ 0⤋
complex situation. lookup on search engines like google. that will can help!
2014-11-04 14:19:57 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Don't cheat. Do your own homework.
2007-02-15 10:23:56 · answer #5 · answered by dmb06851 7 · 0⤊ 0⤋