There are 100 coins in a table and out of these coins, 10 are showing heads and 90 tails.?

Question

There are 100 coins in a table and out of these coins, 10 are showing heads and 90 tails.
A blind man is asked to divide these coins into 2 groups such that the number of heads in each group should be the same. Can he do that ? If yes, how ?

Answer 1

yeah feel which ones are which and flip em so there are even amounts

Answer 2

Note that the piles needn't be the same size! Choose any 10 coins to make one pile, then turn over all 10 coins in that pile. The number of tails in this pile is now equal to the number of tails in the other pile of 90 coins. To see this, suppose there were x tails in the 10-coin pile. Since there were initially a total of 10 tails, there must be 10-x tails in the pile of 90 coins. When you flip over all 10 coins in the smaller pile, the x tails in that pile become heads and the remaining coins, which must be 10-x heads, become tails. That matches the larger pile.

Answer 3

The blind man should just seperate them into 2 groups with 50 each , irrespective of whether it is showong a head or tail because all the coins have a head so there will be 50 heads in each group.

Answer 4

the blind man should just seperate them into 2 groups with 50 each , irrespective of wether it is showong a head or tail because all the coins have a head so there will be 50 heads in each group

Answer 5

yeah because just because its heads or tails, the coins still has both sides... the number of heads remains the same regardless/

Answer 6

well ya siad 10 were heads 90 tails so there allready divided so yes

Answer 7

the coins still have heads even if they are face down

Answer 8

COUNT FIFTY OOUT OF 100

Answer 9

theyve already been divided dude