actually depletion region in a pn unction diode is formed by recombination of electrons and holes near the junction when p-type and n-type semiconductors are joined.so the depletion region acts as a barrier for further movement of carriers across the junction.depletion region consists of immobile ions which does not contribute for conduction.so it creates a potential between the two ends.so a potential greater than the barrier potential should be applied for conduction to take place.
if depletion region is not formed all the carriers would undergo recombination and there will be no possibility for conduction and no possibility of manufacturing electronic goods
2007-02-14 17:55:23
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answer #1
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answered by karthi k 1
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True. It's lightly doped. A forward polarized diode pushes major carriers into the depletion region causing conduction, kinda like pushing two wires together.
2016-05-24 01:41:21
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answer #2
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answered by Anonymous
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in PN junction diode when junction forms then opposite charges start to diffuse on either sides of junction bt after sometime about the junction ucovered ions get accumulated that forms a barrier whose field direction is opposite to that of PN-diode this stops the further diffusion.thus in FB its width reduces & in RB its width increases.
2007-02-14 16:49:24
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answer #3
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answered by Abhilasha C 1
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actually, that takes a long explanation..... Simply saying, Carrier recombination takes place.The majority carriers shifts fromthe respective region to the other region and gets recomined with the minority carriers of that region...
2007-02-14 16:51:41
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answer #4
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answered by Anonymous
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FULL details? that takes at least a chapter of a book - so get reading.
2007-02-14 16:32:48
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answer #5
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answered by Anonymous
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You can some information from this article:
http://en.wikipedia.org/wiki/Semiconductors#Effect_on_band_structure
2007-02-14 18:15:31
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answer #6
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answered by arbiter007 6
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