1)Four forces which are in equilibrium acting on an airplane are…….
a) Lift equals total drag & weight equals thrust.
b) Forward component of weight equals parasite drag & rearward component of lift. weight equals vertical component of lift during glide & turn.
c) Horizontal component of lift equals centrifugal force & vertical component of lift equals weight & parasite drag plus induced drag equals forward component of weight during stabilized glide & turn.
d) Zero thrust plus rearward component of lift and parasite drag equals forward component of weight .weight equals vertical component of lift.
2007-02-13 15:49:59 · 5 answers · asked by tall boy 1 in Cars & Transportation ➔ Aircraft
which anwear shows equilibrium of 4 fourses without omition of others.lift=weight & thrust = drag
2007-02-13 18:55:22 · update #1
While the question is still a mystery...
All of the above are wrong.
1) Equilibriums dont create accelerations, flight is result of a series of controlled departures from equilibrium conditions.
a) Lift and drag are mutually perpendicular, so is the relation between weight and thrust.
b) Drag is never a function of weight
c) Once again, two mutually perpendicular forces are equated (viz. Drag and Lift)
d) Yet again the same equation of mutually perpendicular forces (thrust and lift)
2007-02-13 17:10:33 · answer #1 · answered by ? 6 · 0⤊ 0⤋
None of these are correct. A: is close, if only lift and weight were together and drag and thrust were together. Did you type it right?
2007-02-13 16:40:12 · answer #2 · answered by M333 6 · 0⤊ 0⤋
I agree. none of the above.
In equilibrium:
Lift = Weight
Thrust = Drag
2007-02-13 16:04:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
And so instead of displaying all this brilliant knowledge where is the dumb question?
2007-02-13 15:53:21 · answer #4 · answered by Big C 6 · 0⤊ 0⤋
E) none of the above.
2007-02-13 15:56:57 · answer #5 · answered by Anonymous · 1⤊ 0⤋