how do i convert the polar equation r=6cos (thata) to rectangular form?

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how do i convert the polar equation r=6cos (thata) to rectangular form?

please show me steps!!!

2007-02-13 12:37:47 · 2 answers · asked by Anonymous in Environment

2 answers

Well, by Pythagoras, r=sqr(x^2+y^2). cos theta=x/sqr(x^2+y^2), so substitute these rectangular expressions into your polar equation.

2007-02-13 12:48:42 · answer #1 · answered by zee_prime 6 · 0⤊ 0⤋

r=6cos(theta) : note that this is only possible for -90
r = sqrt(X^2 + Y^2)
x = rcos(theta) => therefore cos(theta) = x/r
sqrt(x^2 + y^2) = 6x/sqrt(x^2 + y^2)
x^2 + y^2 = 6x
y = +/- sqrt(6x - x^2)
note that this can only happen when x is less than or equal to 6

2007-02-13 13:29:24 · answer #2 · answered by six 1 · 1⤊ 0⤋