The gravity field and a mass within has an interaction. Since in every interaction there is a force - counter force effect there must be a force against the inertial force which "pushes back" the gravity field. I have a simple machine which makes spinning around two inertia axis at the same time and it eliminates energy constantly. But where do this energy go? Could it be radiated into the gravity field? I have not succeeded measuring any deflection in the gravity field (yet).
2007-02-13 08:06:03 · 5 answers · asked by Miklós G 1 in Science & Mathematics ➔ Engineering
The moon of the earth is a perfect example of what your questionis all about. The moon has its own gravitational forces, as witnessed by the men walking on the moon. Whereas the moon rotates about its own axis. The earth doing the same descriptive wise, the moon has its mass cg at the center of mass of the earth, that is the moon is really part of the earth. The enery spin you you are ref. to is is totally balanced i an inertia spin as you describe, that is it is negitive and positive return so no energy is lost so of course you will not measure any deflection in the gravitational field whatsoever.
2007-02-13 08:28:08 · answer #1 · answered by James M 6 · 0⤊ 0⤋
No.
You have just created mumbo-jumbo. Mass causes distortion of the gravity field, there is no force pushing back the gravitional field.
2007-02-13 08:09:31 · answer #2 · answered by Mike1942f 7 · 2⤊ 0⤋
As far as I know, there is no known way to have one mass "deflect" the gravity field of another mass.
2007-02-13 08:14:24 · answer #3 · answered by smokingun 4 · 0⤊ 0⤋
Gravity is an illusion!!caused by curved space.
2007-02-13 08:15:20 · answer #4 · answered by The Cheminator 5 · 0⤊ 0⤋
yes, but a mass alone will already generate gravity waves
it doesnt have to accelarate
2007-02-13 08:09:04 · answer #5 · answered by gjmb1960 7 · 0⤊ 0⤋