The way to proceed would be to pump a known current into the solution and measuring the voltage drop across it. Then
R = V/I
The problem is finding a constant current source, this is not an easy task.
If you had an Ammeter, this would be much easier. Plug a 9 volt battery across the solution and measure the current fed to it.
R = 9V/I
You would calibrate this by measuring the exact voltage across the battery.
But then again, if you have an ammeter and a voltmeter, then you probably have an ohmeter and just stick it in the solution and measure the resistance directly.
2007-02-13 07:29:32
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answer #1
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answered by catarthur 6
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Most digital volt meters can be used to measur the 'resistance' of a solution which can be converted into conductivity fairly easily. Just set the meter to the Ohm setting (looks like a horse shoe) and place the two leads into the solution in question.
Two points to consider here are:
1: if the solution is suseptible to trace impurities you have to make sure the meter's metal leads are clean, or attach them to some clean wire
2: if the solution has a very dilute salt concentration (less than 0.1 Molar) you will often have uncompenstated resistance effects that can give misleading values for resistance, capacitance, and conductivity.
best,
me
2007-02-13 07:20:39
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answer #2
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answered by scotter98 3
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One way to measure the conductivity is to use a resistor of a known value in series with a battery and the solution. Ideally the solution should be in a rectangular tank with the electrodes completely covering opposite ends.
Measure the voltage across the resistor. This will permit the current to be calculated. The voltage across the tank divided by this current will equal the resistance of the liquid.
The conductivity will be equal to the inverse of the resistance times the length between the plates divided by the area of one of the plates. It is up to you to use the correct units.
2007-02-13 09:13:08
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answer #3
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answered by Anonymous
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It is used every day in the electronics industry. The electronics industry takes ordinary well or city water which is loaded with minerals and organic materials, puts it thru a filtering process called Reverse Osmosis, To check the quality of water a high voltage is then applied across two electrode rods place at a fixed distance in a glass beaker set up. The voltage is then increased to the point at which a conductance is measured across the electrodes and that is the "quality" of the purified water, Usually the spec is at minimum 20 meg ohm water as calculated from the maximum voltage at discharge across the electrodes. .
2007-02-13 08:35:38
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answer #4
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answered by James M 6
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Take a million liter of distilled water. Insert the voltmeter probes and degree the resistance. (because that's distilled i might want to imagine it might want to be endless) upload x grams of your salt and degree the resistance each and every time you upload the salt. in case you may calculate the PPM (aspects in step with million) each and every of the more desirable sensible or only make a graph showing the change in resistance for each volume of salt you enter. be particular each and every addition of salt is equivalent. Do an identical with NaCl (table salt) and also you'll evaluate the NaCl curve to the CuSO4. the better the concentration of the salt, the decrease the resistance should be. Your instructor can then placed some CuSO4 in a beaker and also try to be in a position to inform him/her the concentration by technique of measuring the resistance and making use of your graphs. besides, that's my advice. abc
2016-11-03 08:55:46
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answer #5
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answered by ? 4
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If it is a multimeter actually, set to measure ohms resistance. A volt measurement will show nothing.
2007-02-13 07:17:42
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answer #6
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answered by waynebudd 6
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what is pizza
2016-05-15 08:01:39
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answer #7
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answered by diane 1
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