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This motor...

http://sargentwelch.com/product.asp_Q_pn_E_WL2454D_ST_A_DC+Motor+Kit_E_

2007-02-12 12:06:50 · 2 answers · asked by Anonymous in Science & Mathematics Engineering

2 answers

It will reduce the resistance, decreasing the voltage (but increasing the current) required for a specific performance. For a particular wanted performance, the power defines how to get it. Example: suppose that you replace a given wire with wire having half the cross-sectional area. The length of the wire doubles, since you are filling the same space, and the resistance goes up by a factor of four. Since you have twice the length, you have twice the number of turns, so the counter EMF generated when the motor is running will be twice as large. Thus, applying twice the voltage, at half the current, gives the same power output as the original.

2007-02-12 12:14:18 · answer #1 · answered by Anonymous · 0 0

Assuming the wire is made of the same material and voltage is consistanct, the resistance is proportional to the cross sectional area of the wire. Smaller wire, higher resistance, bigger wire, lower resistance.
Resistance for 120v is more for 12 AWG than in 000AWG wire.

2007-02-12 20:12:27 · answer #2 · answered by jack w 6 · 0 0

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