a lithium battery with a voltage of 3.6 which has a resistance of 3 k how much current will flow?

Answer 1

please explain what a resistance of 3 k is?

Answer 2

I suspect you want to know what is the amp/hour rating of the battery, and therefore how long the battery will supply current.
A lithium battery of 3.6v is most likely to be found in a mobile telephone. Therefore the load on the battery is dependant on the use of the phone i.e. standing by or talking.
Knowing the internal resistance of the battery means nothing until a load resistance is added.
if the 3K Ohms is in fact the load resistance, then 1.2mA will flow

Answer 3

You obviously mean that the 3k is the 3000 ohm internal resistance of the battery. (3000 ohms! - feels like something wrong here).

This means the max curent flow is 3.6/3000 amps (i'm not going to bother to work it out).

Of course, no current will flow unless the battery is connected to an external circuit. Then, you will have that resistance in series with that of the battery. So, take it into account when doing your calculation.

Answer 4

Using the formula:

V = Ir

You can derive the following:

I = V/r

Which in this case is:

I = 3.6 / 3000

(as 3k = 3000)

so:

I = 0.0012 A

This assumes the resistance of 3K is the load on the battery, if this is the internal resistance, it is impossible to calculate the current flow without knowing the resistance of the applied load.

Answer 5

Approximately 833 amps. You actually gave us P/E=I When you should have given us E/R=I Thus the info you gave us would render you an actual resistance of:4.32mOhms or .00432ohms. Now my question to you is the resistor you're looking at a physical size of 3KW? And if it is what is the actual resistance of the resistor in question. To Im17yrs: Never ASSUME anything dealing with electricity kiddo, that can get you killed. Understood?

Answer 6

You don't mean the cell actually had a resistance of 3K, do you? In that case, the 3K is hoax because your multimeter uses a known voltage to determine resistance, so you can't check the resistance of a powered device.

Answer 7

Ohm's Law is E = I R --- Voltage = Amperage x Ohms. That can be restated I = E/R --- Another way of saying that is current in amps = electromotive force in volts divided by resistance in ohms. Therefore in this problem, I = 3.6/3000
The current will be 0.0012 amps.

Answer 8

Current equals voltage divided by resistance.

Answer 9

Voltage = Current * Resistance, or rearranging:

Current = Voltage / Resistance.

Plug in 3.6 volts and 3000 ohms and you get .0012 amps flowing. See the calculation below for more details.

http://instacalc.com/?d=Q3VycmVudCA9IFZvbHRhZ2UgLyBSZXNpc3RhbmNl&c=dm9sdGFnZSA9IDMuNiB2b2x0c3xyZXNpc3RhbmNlID0gM2sgb2htc3xjdXJyZW50IGluIGFtcHM6fGN1cnJlbnQgPSB2b2x0YWdlIC8gcmVzaXN0YW5jZXx8fA&s=sssssss&v=0.9

Answer 10

If you're talking about time, like two hrs.