YOU HAVE ONLY 2 EGGS & THERE IS A 36 STOREYED BUILDING.NOW U HAVE TO DETERMINE THE STRENGTH OF THE EGGS i.e.,THE HIGHEST FLOOR FROM WHICH IF U DROP THE EGGS,IT WOULD NOT BREAK AND WOULD BREAK IF U DROP FROM THE IMMEDIATE NEXT HIGHER FLOOR.IN OTHER WORDS,IN HOW MANY MINIMUM CHANCES(NOT MAXIMUM)CAN U DETERMINE THE STRENGTH OF THE EGGS?ASSUME THE EGGS HAVE GOOD AMOUNT OF STRENGTH.
2007-02-09 16:34:36 · 8 answers · asked by tarun a 1 in Entertainment & Music ➔ Jokes & Riddles
the first egg did not break when i dropped it from the second floor
the second egg did not break when i dropped it from the 5th floor
yea.. My Eggs Are Quite Strong!!!!
i've reached the 25th floor but the Eggs still haven't broken
2007-02-09 17:12:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
2
2007-02-10 00:46:45 · answer #2 · answered by Artsy-Fartsy-Momma 3 · 0⤊ 0⤋
I interpreted the question as "what test method should be used to guarantee an answer can be found while minimizing the maximum number of tests required".
Once you break egg 1 you have to start testing with egg 2 from the lowest floor that you haven't yet tested from and work your way up 1 floor at a time with egg 2 until it breaks. If you break both egg 1 and egg 2 and you have not tested all floors below the lowest floor from which an egg broke you won't know what the limit is.
To minimize the maximum number of tests required start with egg 1 on floor 8 and continue upward testing with egg 1 until it breaks going next to 15 then to 21 then to 26 then to 30 then to 33 then to 35 then to 36. Once egg 1 breaks (unless it breaks on 36) use egg 2 starting with the lowest floor where you haven't already proved that an egg from that floor or higher won't break (e.g. if egg 1 breaks on 8 start testing egg 2 from 1, if egg 1 breaks on 15 start testing with egg 2 on 9, etc.) . Continue going up 1 floor at a time with egg 2 until it breaks or you get to the floor where egg 1 broke.
The maximum number of tests required will be 8 (1 test with egg 1 & 7 with egg 2, or 2 tests with egg 1 and 6 with 2, or 3 and 5, or 4 and 4, etc. up to 8 & 0).
2007-02-10 01:24:36 · answer #3 · answered by frugernity 6 · 0⤊ 0⤋
2 chances
2007-02-10 00:41:32 · answer #4 · answered by jeeccentricx2 5 · 0⤊ 0⤋
you would have 0 chances minimum (because you dont have to do this) and two chances maximum (you only have two eggs buddy!) ... unless they were boiled, but even then they would splatter!
2007-02-10 01:17:43 · answer #5 · answered by chrysanthemum 2 · 0⤊ 0⤋
GROUND FLOOR BOTH EGGS WOULD BREAK
2007-02-10 01:06:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Ground floor. : )
2007-02-10 00:37:40 · answer #7 · answered by tumbles86 2 · 0⤊ 0⤋
huh?i dot get it =|
2007-02-10 00:40:48 · answer #8 · answered by Dahlia 1 · 0⤊ 0⤋