My system power requirement is between the range of 6.5V to 24V @ 0.8mA w/ GX1 200MHz, in my research I found a 4-cells of battery pack (each cell is 3.6V@ 1.8Ah and 500mA), can this be used for my system? How do I know this battery pack can last for how many hours? What is different between 1.8Ah and 500mA?
2007-02-09 15:23:46 · 2 answers · asked by Leong 1 in Science & Mathematics ➔ Engineering
500 mA is a power requirement and the specified power necessary for your application. Less amperage will not have enough power to overcome the resistence present. Too much amperage or voltage could overheat or otherwise damage your device.
1.8 Ah is a battery capacity. Dividing the power consumption into this number will provide an approximate life expectancy of the battery pack. Remember that 500 mA = 0.5A
1.8 divided by .5 should last 3.6 hours. If the 500mA is a minimum and the device can actually consume more power, the battery may last a shorter time. If the device has a potentiometer (like volume control on your stereo) than it may also be possible to turn down the volume in which case you may be consuming less than 500 mA and the battery will last longer.
2007-02-09 16:25:33 · answer #1 · answered by MrWiz 4 · 0⤊ 0⤋
1.8Ah rated battery implies that it can deliver 1.8A of current for one hour. Its called the capacity of the battery.
500mA requirement of the device implies that the device needs 500mA of current at rated voltage for its functioning.
since it is rated at 6.5 to 24 V, 3.6V*4=14.4V
hence Ur battery can drive the device.
considering 1.8Ah battery,
current its 1.8A, so it can deliver 0.8mA(your device rating) of current for (1.8/0.8m)x1hour=2250 hours.
now to be accurate, 14.4V* 0.8mA=0.01152w is ur device power consumption.
I hope am right. And U got ur answer.
Thank you
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2007-02-09 15:45:38 · answer #2 · answered by Prabhanjan 2 · 0⤊ 0⤋