A line of 100 airline passengers is waiting to board a plane. They each hold a ticket to one of the 100 seats on that flight. (For convenience, let's say that the nth passenger in line has a ticket for the seat number n.)
Unfortunately, the first person in line is crazy, and will ignore the seat number on their ticket, picking a random seat to occupy. All of the other passengers are quite normal, and will go to their proper seat unless it is already occupied. If it is occupied, they will then find a free seat to sit in, at random.
What is the probability that the last (100th) person to board the plane will sit in their proper seat (#100)?
2007-02-08 14:19:20 · 7 answers · asked by Anonymous in Entertainment & Music ➔ Jokes & Riddles
The whole thing stops when someone else sits in Crazy Guy's seat. The chances of that range from 1/99 (First person) to 1/1 for the last guy. So:
1/99 + Summation from 98 to 2 of ( 1/ n(n+1) )
This returns 0.5 or 50%.
Also, the answer remains 50% no matter how many people are added to the line!
2007-02-08 14:48:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋
it will be 1 in 10000
2007-02-08 22:25:44 · answer #2 · answered by marlin 2 · 0⤊ 0⤋
Not very much considering that dude stole your seat
2007-02-09 00:10:26 · answer #3 · answered by qųěęŋ ŏf ħęãŗţş 3 · 0⤊ 0⤋
wow this is much to complicated for this late at night lol and not all that funny either which is y i came to jokes
2007-02-08 22:42:56 · answer #4 · answered by crazyme 5 · 0⤊ 0⤋
1/1.2120287719992724101519381669645e+156
2007-02-08 22:29:23 · answer #5 · answered by bassooncrazy 2 · 0⤊ 0⤋
who the hell knows..lol
2007-02-08 22:23:37 · answer #6 · answered by tamitones1978 3 · 0⤊ 0⤋
I/IOO
2007-02-08 23:50:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋