2007-02-08 13:27:47 · 5 answers · asked by stumped on physics 2 in Science & Mathematics ➔ Engineering
Your answer cannot be determined with the information you presented. The impedance involves the capacitance (which you gave) but also includes capacitive reactance and inductive reactance.
2007-02-08 13:31:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Z = 1/(jwC), where j is the square root of -1, w is the angular frequency in radians per second, and C is the capacitor value in Farads.
If there is no resistance in the capacitor (ideally, there isn't), then there is no real component of the complex number. And the impedance of the capacitor is also its absolute value of impedance.
2007-02-08 14:48:26 · answer #2 · answered by vrrJT3 6 · 0⤊ 0⤋
I concur with greencreeper; a capacitor acts as an open for a DC circuit so the "impedance" (OK, its not really impedance) would be infinite and acts differently at different frequencies with ac circuit. At a very high frequency the cap will appear to take on the characteristics of an inductor.
2007-02-08 13:50:55 · answer #3 · answered by Anonymous · 0⤊ 0⤋
First, capability element = genuine/VA = cos(section attitude) cos(section attitude) = 40/fifty seven section attitude = 40 5.40 3 tan(section attitude) =X/R tan(40 5.40 3)=X/50 X=50.seventy six IimpedanceI=sqrt(R^2+X^2) IimpedanceI = 71.25 ohms :)
2016-12-17 05:41:31 · answer #4 · answered by lacross 4 · 0⤊ 0⤋
In ohms and assuming negligible resistance,
1/(2pi*f*C),
with C in Farads and f in Hertz
2007-02-08 15:18:58 · answer #5 · answered by Gary H 6 · 0⤊ 0⤋