I'm doing Moment Distribution.
2007-02-06 08:26:41 · 2 answers · asked by graciedai 2 in Science & Mathematics ➔ Engineering
The beam (30' long) is fixed on both ends with 2 concentrated loads (each 20 kips) pointing down at 10' from both ends.
2007-02-06 10:39:44 · update #1
The fixed end moments are -2PL/9 at the left end and +2PL/9 at the right end, where P = 20k and L = 30'
M left = -2*20*30/9 = -133.333 ft kips
M right = +133.333 ft kips
2007-02-07 01:54:45 · answer #1 · answered by minorchord2000 6 · 0⤊ 0⤋
I don't have my references with me but you can find this and almost all other typical cases in one of two books.
Manual of Steel Construction by AISC
"Formulas for Stress and Strain" by Roarke.
If you don't already have a MSC (or more commonly, The Manual), you can find one at the library or ask a senior. They will have had to buy one for their steel design classes.
2007-02-06 08:35:36 · answer #2 · answered by Imagineer 3 · 0⤊ 0⤋
We need the geometry of the problem. How is the beam supported, where are the loads, and what direction are they oriented?
2007-02-06 08:30:46 · answer #3 · answered by Argon 3 · 0⤊ 0⤋