Coors-light and a twelve-pack of Mich.-light (not necessarily in that order)!!!!!!!!!!!! Which did I enjoy the most????? C'mon, people answer this one!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
2007-02-05 18:59:38 · 11 answers · asked by Mr.YES-MAN 2 in Food & Drink ➔ Beer, Wine & Spirits
my guess is your favorite beer is the next one coming up
2007-02-05 20:41:32 · answer #1 · answered by murduk0420 3 · 1⤊ 0⤋
Those are good premium beers... next time try some of those ICE beers... I suggest NATURAL ICE and BUD ICE. These beers are 5.9% ALC/VOL and light on the calories, less expensive and you get a quicker buzzzzzzzzzzzz than those 4.2% ALC/VOL premium beers. By the way an answer to your question... COORS LIGHT... that rocky mountain water is goooooooood.
2007-02-06 05:13:47 · answer #2 · answered by william p 2 · 1⤊ 0⤋
you must really like pissing because that is the only good reason for drinking that many light beers. Why dont you quit counting how many beers you drink and start drinking a dark beer, nobody cares how many beers you can drink especially if its a light beer.
2007-02-06 13:24:48 · answer #3 · answered by Sir Smoke-a-lot 3 · 0⤊ 0⤋
Coors-light... Maybe, which one did you drink 1st, that one is it cause you chose it 1st....
2007-02-06 03:17:01 · answer #4 · answered by Livier A 3 · 1⤊ 0⤋
Is that all and only light beer.
2007-02-06 03:06:32 · answer #5 · answered by Leroy 3 · 1⤊ 0⤋
couldnt have been either because they are both very crappy beer next time drink a 24 of labbat black ice then tell me about it
2007-02-06 08:46:12 · answer #6 · answered by Anonymous · 0⤊ 1⤋
You enjoyed them equally because you stole them from someone's refrigerator.
2007-02-06 03:05:17 · answer #7 · answered by jammer 6 · 2⤊ 0⤋
More importantly, we want to know how you are feeling this morning.
2007-02-06 06:21:28 · answer #8 · answered by MaryCheneysAccessory 6 · 1⤊ 0⤋
Michelob, because it is more expensive.
2007-02-06 05:00:56 · answer #9 · answered by jayevans2121 2 · 1⤊ 0⤋
Was that for breakfast?
2007-02-06 03:09:17 · answer #10 · answered by Murray H 6 · 1⤊ 0⤋