It says my girlfriend has been "active during the past 24 hours" in the search listings of personals in my area?? How can this be? :(
Does being on the Yahoo network (like IM, email, etc) make you "active" or does this means she's active on Yahoo personals!?!?!
2007-02-04 21:33:17 · 7 answers · asked by Harry M 1 in Family & Relationships ➔ Singles & Dating
NOOOOOOOOO!
She is definitely up to no good. If she loves you, she would not be looking for "Personals" in your area.
My advice, dump her, she is not ready for a commited relationship.
Good Luck
Apie
2007-02-04 21:42:02 · answer #1 · answered by Apie 2 · 1⤊ 0⤋
It means she is active on yahoo personals if thats what it says when you do a yahoo personals search. Ask her about it. Good luck
2007-02-04 21:36:03 · answer #2 · answered by jasmyn 3 · 0⤊ 0⤋
no, it means she has been actively checking other people's profiles and other have been checking her profiles out, active mean only for yahoo personal. not for IM. and btw you are also checking yahoo personal too, then I guess it makes it alright for her to do it as well. yeah?
2007-02-04 21:37:09 · answer #3 · answered by Mike 4 · 1⤊ 0⤋
She is active on yahoo personel and maybe in a process of finding someone new.Take care of her.You may not be as loving as you ought to be,
2007-02-04 21:43:31 · answer #4 · answered by jus-tus 3 · 0⤊ 0⤋
It means she looked. Doesn't mean she's cheating. Maybe just bored and decided to look at her profile to see if any new messages trickled in since she met you. Not that she would respond to anything. Why is her profile still up anyway?
2007-02-04 21:39:16 · answer #5 · answered by itry007 4 · 0⤊ 0⤋
Yo galfrend has the right of doing other things apart from being yo galfrend.ask her if u want to start a fight.r u going to handle it if she becomes all over u that u cant even breath.
2007-02-04 21:49:36 · answer #6 · answered by lady x 3 · 0⤊ 1⤋
Oh yeah. She is "active" alright. I got personal with her last week.
2007-02-04 21:42:45 · answer #7 · answered by edward_the_l0ngshanks 4 · 0⤊ 2⤋