Describe an experiment that could be used to confirm Ohms law?

Question

Describe how this could be used to prove only Ohm’s law applies to resistances that display linear characteristics.

Answer 1

heh...
I just love circuts...

First the dry info....(one line only)
"Material that obeys Ohm's Law is called "ohmic" or "linear" because the potential difference across it varies linearly with the current. "

NOW!!! the fun stuff!! Here's a little program you can use to experiment with different powers and resistors and decide what you want to use to make your own REAL circut...

http://www.walter-fendt.de/ph11e/ohmslaw.htm

It's coming from this EXCELLENT explanation of OHM's law....

http://www.physics.uoguelph.ca/tutorials/ohm/Q.ohm.intro.html

And, this next site shows you the chart you should write up to show off the work you did!

http://www.batesville.k12.in.us/physics/PhyNet/e&m/current/labs/ohms_law.htm

hope I helped

-dawgy

Answer 2

From what I remember, OHM used a spring and different pieces of wire.

The Piece of wire was held taught with a spring. Then, the battery was connected and current was allowed to flow. After a period of time, the wire would heat up and the spring would bend the wire a certain distance with respect to the voltage applied.

Well, try that with different types of wires (Aluminum, Copper, Iron, etc) and different voltages.

What you could do instead of that is use different resistors or "pieces of resistance" and a long piece of wire. You will have to increase the voltage until the wire heats up to "red hot" and is allowed to bend/stretch. A really thin piece of copper wire could be used, so you don't have to use a really high voltage, but the piece of wire still has to turn red hot and be allowed to stretch.

Answer 3

right it truly is how i glance at it. There are 2 varieties of voltage. One is a source voltage together with a battery and the different is a stepped forward voltage together with the voltage as by way of the cutting-edge flow via a resistor. cutting-edge is instantly proportional to an utilized source voltage throughout a resistance. for that reason cutting-edge relies upon on the amplitude of the voltage and so i = V/R. while a stepped forward voltage throughout a resistance is instantly proportional to the cutting-edge via the resistance. for that reason the voltage via the resistor relies upon on the present that is being forced via the resistor through an exterior source and so (e of R) = (I of R) x R. after all in case you don`t comprehend if V is a outcome of I or I is a outcome of V we may be able to continually say that V = IR see you later as we are tailing about DC circuits.