6 cells are connected in series to form one battery. Ea cell has a rating of 1.5V and 1A. AWG 18-ga wire joins the + terminal of the battery formed by the series to an indicator lamp located 300ft away. another 300ft length of AWG 18ga wire runs from the lamp back to the battery's neg pole. The lamp acts as a 50 ohm resistor.
1. total voltage and amperage supplied by battery?
2. total resistance resulting from 600ft of 18ga wire?
3. total voltage drop across wire?
4. total voltage drop across lamp?
Please show formulas used to calculate answers. Stuck on this one bigtime.
Thanks!
2007-02-04 02:25:59 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Use the link to calculate resistance of your wire. Multiply the voltage per cell by number of cells to get total voltage at battery terminals. Use formula E = IR (transposed) to calculate I (amps) where R will be sum of wire and bulb resistance. Use E = IR a second (and third) time to calculate E (voltage drop across lamp (or wire) knowing I (amps) and R of each load. It usually helps to draw a diagram (circuit) showing battery, wires and lamp labeled with voltage, current and resistances as you determine them. A picture is worth the proverbial 1,000 words. Good luck.
2007-02-04 03:26:20 · answer #1 · answered by Kes 7 · 0⤊ 0⤋
1= 9volts and 1.8amps
2= 2.222 ohms
3= 4volts
4= 5volts
ohms lam...... I=V/R V=IR R=V/I
Kirchoffs Law V1=0=V2
Been a while.....
2007-02-04 04:25:35 · answer #2 · answered by Big B 2 · 0⤊ 0⤋