a rigid tank contains 6kg of an ideal gas at 3atm and 40 degree celcius. now a valve is opened and half of mass of gas is escaped.if the final pressure in the tank is 2.2 atm. find the final temperature.
2007-02-02 03:48:09 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
The mass of the gas is irrelevant.
If there was no temperature change, halving the gas would drop the tank pressure from 3 atm to 1.5 atm. That's what the ideal gas law says.
So to exert 2.2 atm, it must be hotter by a ratio 22/15 in absolute temperature. That’s what the ideal gas law says again. Absolute is Celsius plus 273. So (273 + 40) * 22/15 = 459 absolute = 186 Celsius.
2007-02-02 04:01:30 · answer #1 · answered by Anonymous · 1⤊ 0⤋
You should be able to use P1V1/T1= P2V2/T2. When you let half the gas out of the container, you basically increased the volume to 2 times the original. So, use V for V1 and 2V for V2, and then solve for T2. The V will cancel out.
2007-02-02 03:55:07 · answer #2 · answered by hcbiochem 7 · 1⤊ 0⤋