I lost my drivers license and am flying tomorrow, can i use my passport at check in and security checks?
2007-02-01 09:53:09 · 12 answers · asked by Leigh 3 in Travel ➔ Travel (General) ➔ Other - Destinations
Yes you can use a passport for ID for domestic travel. I do this regularly because I find it easier to handle (and not lose) than my driver's lic.
For proof of ID, an expired passport is acceptable.
The passport only needs to be current if you are using it for foreign travel.
2007-02-01 10:26:21 · answer #1 · answered by mary4882 4 · 1⤊ 0⤋
Absolutely yes, if it is a valid Passport, as in not expired. If you're traveling internationally you have to use a passport and a State issued License would be almost useless.
2007-02-01 09:58:27 · answer #2 · answered by lucky13ek 2 · 1⤊ 0⤋
A passport is usually the ID of choice at airports these days!
2007-02-02 03:19:56 · answer #3 · answered by Roxanne G 2 · 1⤊ 0⤋
A passport is the absolute best type of ID you can provide!!!! You should have no problems at all with your passport. Have a good trip.
2007-02-01 12:56:05 · answer #4 · answered by catchernkeeper 2 · 1⤊ 0⤋
Usually you can. A passport is harder to get than a DL so it should be fine. You might want to take other forms of picture ID though just in case.
2007-02-01 10:03:42 · answer #5 · answered by Karen 4 · 1⤊ 0⤋
Yes, your passport counts as photo ID.
2007-02-01 10:02:51 · answer #6 · answered by amberpatience 4 · 2⤊ 0⤋
You need to get an international drivers license. Call AAA or other travel agency.
2007-02-02 06:08:00 · answer #7 · answered by jmp_omaha 3 · 0⤊ 0⤋
I would think so since both Puerto Rico and the US Virgin Islands are US Territories so travel to those places would be just like traveling to any other US state. Good luck and happy traveling!
2016-05-24 03:07:02 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Yes.
2007-02-01 10:00:56 · answer #9 · answered by Anonymous · 1⤊ 0⤋
You should be able to use it. All they require is a picture ID and that covers it.
2007-02-01 09:56:30 · answer #10 · answered by CctbOh 5 · 1⤊ 0⤋