Theorem : 3=4
Proof:
Suppose:
a + b = c
This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c
After reorganising:
4a + 4b - 4c = 3a + 3b - 3c
Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)
Remove the same term left and right:
4 = 3
2007-01-31 12:43:20 · 7 answers · asked by sprinting_turtle 5 in Entertainment & Music ➔ Jokes & Riddles
There is a divide by 0 error. (a+b+c)=0 so you can not divide that.
2007-01-31 12:49:24 · answer #1 · answered by Ace 5 · 1⤊ 0⤋
i think where you went wrong is the second line
see it should be (4a-3a)+(4b-3b) = (4c-3c)
it is a mathematical problem splitting up the a's b's and c's
2007-01-31 13:19:00 · answer #2 · answered by homer s 2 · 0⤊ 0⤋
yeah, what ace said.
suppose a=2, b=3, c=5. the last step of the solution, requires that both sides be divided by (a+b-c). substituting, we find (2+3-5) = 0. since dividing by zero is undefined, this last step is invalid.
2007-01-31 13:58:44 · answer #3 · answered by mckinneyb89 1 · 0⤊ 0⤋
If a+b=c, then a+b-c is the same as c-c, which, no matter what c is, equals 0, so you can't factor a+b-c out of the equation.
2007-01-31 16:28:08 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Haha, interesting...
2007-01-31 13:41:22 · answer #5 · answered by ViCKi!™|` 5 · 0⤊ 0⤋
thanx for that, i've stared your question.....
2007-01-31 13:14:03 · answer #6 · answered by Anonymous · 0⤊ 0⤋
i dont know wat the f**ck yall talkin' bout cuz im in the 6th grade soooooooooooo....................
i bet it is funny
(if i understood)
2007-01-31 12:53:22 · answer #7 · answered by Anonymous · 0⤊ 0⤋