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2 answers

(5280 feet/mile) * (1 cone/4 feet) + 1 cone at the "zero" = 1321 cones

Done.

2007-01-31 06:55:07 · answer #1 · answered by Jerry P 6 · 1 0

1321, assuming a cone was put at 0' and 5280'.

5280 / 4 = 1320 spaces
1320 spaces = 1321 cones

2007-01-31 13:06:54 · answer #2 · answered by bsah 3 · 1 0

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