2007-01-30 10:32:37 · 3 answers · asked by kawaii_niikii 2 in Science & Mathematics ➔ Engineering
Any linear circuit that dissipates electrical power can be represented by an equivalent Thevinin or Norton circuit. A TV's power supply is not a linear device, so you really can't model a TV as a resistor by itself. If all you care about is power dissipation, you can make a grossly inaccurate model by saying the TV's "equivalent resistance" dissipates the same average power as the TV.
2007-01-30 11:04:21 · answer #1 · answered by Jess 2 · 0⤊ 0⤋
Almost anything in an electrical circuit has resistance. So the TV is a 'LOAD'. Simply meaning it offers some amount of resistance, because it is dissipating energy
2007-01-31 02:21:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Not actually a "resister", but I suppose it could be thought of as one when it is considered as a simple load.
If we know the voltage and current draw of the TV, we can figure its effective resistance. R=E/I where E=voltage, I=current and R=resistance.
2007-01-30 18:52:26 · answer #3 · answered by LeAnne 7 · 1⤊ 0⤋