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Calculate the standard enthalpy change in kJ for the production of 15.2 g of H2O(g) from a reaction where the reactants and products are:

reactants: H2S (g) O2 (g)

products: H2O(g) SO2 (g)

2007-01-29 12:28:17 · 2 answers · asked by Anonymous in Science & Mathematics Engineering

2 answers

S=(A*c^3)/(4hG)

2007-01-29 16:40:02 · answer #1 · answered by Jesters Deadd 2 · 0 0

First you need to write a balenced reaction.

H2S + O2 => H2O + SO2

your enthalpy change will be

the enthalpy of H2O + the enthalpy of SO2 - the enthalpy of O2 - the enthalpy of H2S

gives the enthalpy per mol and solve for (15.2 g/ 18) moles
I believe the enthalpy of O2 is zero but the rest can be looked up.

2007-01-29 21:11:38 · answer #2 · answered by LGuard332 2 · 0 0

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