Suppose that the voltage measured on a voltmeter is 15V. The calculated value of the voltage was 14.2 V. Compare the % error for this laboratory experiment.
2007-01-29 06:21:21 · 3 answers · asked by RITA 1 in Science & Mathematics ➔ Engineering
% error=(1-((Actual value)/(Theoretical value)))*100
AV=14.2
TV= 15
So the error is 5.33%
It's very much understandable. There's energy dissipation through the wires, and the wires themselves have resistance.
2007-01-29 07:24:06 · answer #1 · answered by womfalcs7 2 · 0⤊ 0⤋
Error is usually defined as the sum of the correct value minus the experimental value divided by the correct value and multiplied by 100%. Or... Err%=(Actual-Measured)/Actual*100%.
In your case:
Err%=(15-14.2)/15=5.33%
2007-01-29 15:43:44 · answer #2 · answered by deken_99 2 · 0⤊ 0⤋
5.33%
2007-01-30 06:25:18 · answer #3 · answered by GGGGHHH G 1 · 0⤊ 0⤋