A ball is travelling with a speed of 35m/s when it make contact with a wall, if the contact stayed for 0.05s and the ball leaves the wall with a speed of 55m/s.
i) what's the change in momentum?
ii) what average force did the wall exert on the ball to cuse the change in momentun?
2007-01-28 06:47:34 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Momentum is mass * velocity. Since you do not give the mass I will have to use m to represent the mass. Momemtum is also a vector with magnitude and direction. So the momentum going toward the wall is 35m and away from the wall 55m in the opposite direction. So the change in momentum is (35 + 55)m = 90m
To answer part two you need to know that Force = change in momemtum / time so in this case we have 90m/.05 = 1800m
2007-01-28 07:01:53 · answer #1 · answered by rscanner 6 · 0⤊ 0⤋