A man is walking his dog on a lead towards home at a steady 4 mph. When they are 10 miles from home the man lets the dog off the lead. The dog immediately runs off towards home at 6 mph. When the dog reaches the house it turns around and runs back to the man at the same speed. When it reaches the man it again turns back for the house. This is repeated until the man gets home and lets in the dog. How many miles does the dog cover from being let off the lead to being let in the house?
2007-01-26 03:58:26 · 6 answers · asked by Rajeev N 1 in Pets ➔ Dogs
Some questions are just too much trouble to answer and this is one of them. If I wanted to do math, I would go to a different section. However, I do know I get 2 points for answering.
2007-01-26 04:17:08 · answer #1 · answered by st.lady (1 of GitEm's gang) 6 · 0⤊ 0⤋
I love math. The dog will travel 15 miles. Need to work it out?
Distance = rate x time. The man will end up traveling 10 miles at a rate of 4 mph. So, it will take him 2.5 hours. Using the same formula, if a dog is running at a rate of 6 mph for 2.5 hours (the time it takes the man to get to the door), the dog is running for 15 miles.
2007-01-26 12:45:04 · answer #2 · answered by Pink Denial 6 · 0⤊ 0⤋
More than the man?
2007-01-26 12:09:08 · answer #3 · answered by coolhandven 4 · 0⤊ 0⤋
he still has coverd the same distance put has ran a lot more than the distance traveled
2007-01-26 12:03:21 · answer #4 · answered by aussie 6 · 0⤊ 0⤋
r u trying to cheat with your home work?
2007-01-26 12:59:55 · answer #5 · answered by tyro_w 1 · 0⤊ 0⤋
Sorry, you have to do your math homework yourself.
2007-01-26 12:18:52 · answer #6 · answered by doggzma 3 · 0⤊ 0⤋