And / Or / Not Gates?

Question

lets say two inputs go into a AND Gate |__) , if one is a 1, and the other is a 0, what happens in the gate ? Does the input just dead end since it cant go through or does it just skip the gate entirely ?

Answer 1

Your question suggests that you have a misconception.
A logic gate isn't like a pipe with a valve. The input signals don't "pass through" in the sense you are talking about. The input signals are inputs to an amplifier, and the output signal is the output of the amplifier. The inputs and outputs are electrically isolated.

If you examine current flows, the input currents are very small. At the chip level, a single output pin can usually drive a large number of inputs; the number is called the "fan out" of the amplifier. Current sourced by the output pin comes from the power supply of the chip, and current sunk into the output pin goes to the ground pin of the chip.

So, in the sense you are talking about, all the inputs are "dead ends" all of the time.

Answer 2

The output of an AND gates is only a 1 when all inputs are a 1.If you put in a 1 and a 0, the output is a 0 (low voltage).

Answer 3

The Answer is

Truth Table of AND Gate

A(input 1) B(input2) C(output)

0 0 0
0 1 0
1 0 0
1 1 1
i hope this will solve. If you ask Electronically, you can understand using Transistor logic that only if both inputs are high out is not grounded, anyone if low makes output to be grounded creating 0 volts.

Answer 4

for a 1 signal to occur

In 2 input OR gate you must have a 0 and 1, 1 and 0

In a 2 input AND gate you must have a 1 and 1

In a 2 input NOR gate you must have 0 and 0

Answer 5

You put logic signals into gates and you get logic signals out. 1 is the high level and 0 is low. What the actual voltage values are depends on the logic.

In this case you will get a 0 out. You can think of it as a dead end if you like.

Answer 6

it doesnt die for nothing!
The HIGH input "frees" enough electrons from the p-n junction in the transistor to let electicity flow from the emmiter toward the base , but if the other input is LOW the electrons will pass toward it and the output of the gate will be 0.