my results are 20
2007-01-24 17:08:23 · 3 answers · asked by princess 1 in Science & Mathematics ➔ Engineering
IF the square face has dimensions of e X e and the height is 6
the total area formula would be A= 4 (sides) + 2 (faces)
2
120 =4 (6e)+2 (e)
2 2
60= 12e + (e) ; (e) + 12e - 60 = 0; solve for e = 3.8 yd
(When this presents, the 2's will be mislocated. Thy should be above the (e) factors representing squares.)
2007-01-24 20:30:52 · answer #1 · answered by Bomba 7 · 0⤊ 0⤋
the whole area is A= 4*side area+ 2*base area
suppose the base edge lenght is x
so the side area is 6*x
the base area is x^2
A=4*6*x + x^2
120 = 24x + x^2
x^2+24x-120=0
by solving this equation ( Delta=384)
the roots are
x1=3.8
x2=-15.8
so the base edge lenght is 3.8 yd
2007-01-25 15:42:56 · answer #2 · answered by Moutassem A 1 · 0⤊ 0⤋
The length of a base edge is 5.77yd
2007-01-25 01:36:38 · answer #3 · answered by hartless63 4 · 0⤊ 0⤋