Say that a town has 1,000 residents,of whom 60% are women and 40% are men.Of the women,40% wear one earring.Half of the rest wear 2 earrings,and half wear none.Of the men,60% wear one earring.Half of the rest wear two earrings,and half wear none.How many earrings are worn in all?
2007-01-24 13:49:39 · 6 answers · asked by Aquafina 1 in Education & Reference ➔ Other - Education
Given: 1000 people ; Women = 60% = 600;
(Women w/ 1 earring = 40% of 600 = 240;
(Women w/ 2 earring = (600 - 240) / 2 = 180;
(Women w/ none) = 180
Men = 400;
(Men w/ one earring) = 60% of 400 = 240;
(Men w/ two earring) = (400 - 240)/ 2 = 80;
(men w/ none) = 80
Total earrings = Women: [(240 + (180 x 2)] + Men: [(240 + (80 x 2) ] = 1000 earrings!!!!!
2007-01-24 13:59:52 · answer #1 · answered by Student_007 1 · 1⤊ 0⤋
Exactly 1000 (the ppl wearing two earings account for those not wearing any).
2007-01-24 14:00:49 · answer #2 · answered by Chet Vonga 1 · 0⤊ 0⤋
think about it, half wearing none and half wearing two is the same as all of them wearing one. you can do it if you take your time
2007-01-24 13:56:43 · answer #3 · answered by little ole me 2 · 0⤊ 0⤋
1,000 ear rings.
2007-01-24 14:12:47 · answer #4 · answered by Phlow 7 · 0⤊ 0⤋
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2007-01-24 13:59:08 · answer #5 · answered by Cutie 4 · 0⤊ 0⤋
Say
2007-01-24 13:51:59 · answer #6 · answered by Evtm 2 · 0⤊ 0⤋