If the current is equal in all series circuits, how does it increase...for instance, leds burning out in series and no tin parallel.
2007-01-24 10:56:48 · 6 answers · asked by a a 1 in Science & Mathematics ➔ Engineering
Led's don't burn out they typically short out. So if you have a string of leds in series and one shorts out, you will have more voltage across each led therefore more current flowing thru each lit led. For each led that shorts out your voltage/current on your existing lit leds will increase. If many led's short out your whole string will eventually short out because of the led's can't handle the additional current.
2007-01-27 15:12:31 · answer #1 · answered by biomedking 2 · 0⤊ 0⤋
In a parallel circuit, the current through each LED will be the same - it is dependent on the source voltage and the resistance of the LED.
It won't matter if you have 1 LED or 20 LEDs, each will be subjected to the same voltage. And 1 LED will be the same brightness as each of any number of LEDs in a parallel circuit.
Think of your lights in your home - your home is wired in parallel - if you have 1 light on or 20 lights on the same circuit, it doesn't matter. Each light will be subjected to 120 VAC.
In series, each LED will cause a voltage drop to occur across the LED - the sum of the total voltage drops will always equal the source. The more LEDs you have strung together, the less voltage across each LED because the total resistance is raised and the current is lowered, and the dimmer the LED. The total current throughout the entire circuit and through each LED will be the same. Again, this current will depend on the total number of LEDs.
The most common cause of a LED failure is excessive current - usually the result of excessive voltage across the LED. If your LEDs in series are burning out, either the source voltage is too high or you don't have a sufficient number of LEDs in series for the voltage used.
2007-01-24 12:04:03 · answer #2 · answered by LeAnne 7 · 0⤊ 0⤋
Current is equal in all elements of a series circuit.
If you are burning out Leds you need to put in some current
limiting.
2007-01-24 11:01:01 · answer #3 · answered by trichbopper 4 · 0⤊ 0⤋
If you got 3 light bulbs in series the electricity travels through each one in a line. If you blow one light then you stop the flow from travelling to the next light and so there is no electrical flow.
If you got 3 light bulbs in parrallel then the current is distributed to each light (although the voltage is same for each light) and if one light blows then the current is distributed more so to the remaining two lights... thereby increasing the power to the two other lights (often making them brighter).
2007-01-24 11:04:25 · answer #4 · answered by haratu 4 · 0⤊ 0⤋
It relies upon. upload it in sequence and the present is going down. upload it in parallel and the present is going up. DC is the elementary case however the kinfolk stay the comparable for AC. Ohm's regulation states: I=V/R the place I=contemporary V=voltage & R=Resistance (measured in ohms) in case you have 10 volts, going to a ten ohm circuit you get a million amp = 10v / 10ohms. in case you upload yet another 10ohm circuit in sequence, the resistance is additive, so which you get .5A = 10v / 20ohms. yet upload yet another circuit in parallel, the resistance is a million/R = a million/r1 + a million/r2. r1=circuit a million, r2=circuit 2 So a million/R = a million/10ohms + a million/10ohms a million/R = 2/10ohms R = 10ohms/2 R = 5ohms So now you get 2A = 10volt / 5 ohms once you're speaking approximately family contributors circuits they're under pressure in parallel, so plug in extra gadgets and the present draw is going up.
2016-12-16 16:36:59 · answer #5 · answered by Anonymous · 0⤊ 0⤋
confusing situation. do a search onto yahoo and bing. that may help!
2014-11-14 20:34:24 · answer #6 · answered by ? 3 · 0⤊ 0⤋