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the idea is simple a chargable battery which is charged by ac line power .then one induction motor controlled by induction motor drives for wheels and other things who is ready to share what she/he knows??

2007-01-24 10:12:37 · 3 answers · asked by nima_iran_1985 3 in Science & Mathematics Engineering

3 answers

It seems to me that one motor for each wheel makes the greatest sense. For most driving conditions, only the front and/or rear wheels need to provide the power. In a down hill or braking situation, a computer module could control an SCR panel and convert the motors to generators, thus returning a percentage of the kinetic energy of the vehicle back into electric energy and, ultimately, back into the batteries.

You will need a light vehicle, efficient motors and light, efficient batteries.
The basic hurdles to your plan seem to me to be the amount of electricity that's needed to obtain a reasonable amount of horsepower that will be necessary to accelerate a vehicle in a safe and acceptable way - (~746 watts = 1 horsepower) - we've been spoiled by the modern internal combustion engine with it's considerable power output and range between refueling capabilities.

It'll take a hell of an electric vehicle to convert most drivers to electric - either that, or a fuel price that'll lower their expectations considerably.

2007-01-24 12:29:21 · answer #1 · answered by LeAnne 7 · 0 0

AC induction motors are currently used in modern electric vehicles like the Tesla:
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http://www.teslamotors.com
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And the Phoenix:
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http://www.phoenixmotorcars.com
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These are both very interesting cars, and show us the future of electric vehicles. The Tesla can accelerate faster than a Ferrari, and gets 250 miles per charge.

The Phoenix also gets up to 250 miles per charge, can carry 5 passengers plus cargo at 95mph, and can be charged in only TEN minutes.

2007-01-27 13:44:54 · answer #2 · answered by apeweek 6 · 0 0

Induction motors work for the London Underground. You'll need some very big batteries though

2007-01-24 18:34:52 · answer #3 · answered by Anonymous · 0 0

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