If you mixed 8.0 tons of sand, 12 tons of rock, and 4.0 tons of cement to make concrete, what would the percent by weight of sand be
2007-01-23 11:15:28 · 7 answers · asked by tamdj2001number1 1 in Science & Mathematics ➔ Engineering
First off you need to know the total weight of everything in the concrete... 8 tons + 12 tons + 4 tons = 24 tons.
What you now need to find is... what percentage is 8 of 24? To do this divide 24 by 8 to get 0.333333 and then because it's percent you need to multiply by 100. The answer is 33.333% (one third).
2007-01-23 11:20:40 · answer #1 · answered by Trevor 7 · 0⤊ 0⤋
33%
8+12+4 = 24 tons
8 tons of sand / 24tons total = 1/3 = 33%
2007-01-23 19:18:17 · answer #2 · answered by Michael Dino C 4 · 0⤊ 0⤋
This may be a trick question. To make concrete, you would also need to add water to the mix. That would change the percentages that have been previously reported. Also, because the sand itself may contain water, depending on its moisture content, this may affect the answer. Do you want the percentage of sand in an oven-dry state or some other moisture state? Same problem with the rock.
2007-01-24 15:22:49 · answer #3 · answered by violin260 2 · 0⤊ 0⤋
8/(8 + 12 + 4) = 8/24 = 1/3 = 33.33%
2007-01-23 19:19:38 · answer #4 · answered by frugernity 6 · 0⤊ 0⤋
33%
2007-01-23 19:34:17 · answer #5 · answered by B W 2 · 0⤊ 0⤋
33.3333333
2007-01-23 19:39:33 · answer #6 · answered by techengr36 2 · 0⤊ 0⤋
approx. 33.3%
2007-01-23 19:25:24 · answer #7 · answered by notaxpert 6 · 0⤊ 0⤋