2007-01-22 01:28:56 · 7 answers · asked by superliftboy 4 in Science & Mathematics ➔ Engineering
I have an excel spread sheet that does this, if you email me at
hypno_1973@yahoo.co.uk
I'll forward the spread sheet to you.
2007-01-23 00:55:08 · answer #1 · answered by psychic_hedgehog 2 · 0⤊ 0⤋
The Voltage Drop V on a single conductor is given by V = I x Z where Z is the total impedance of the conductor.
For all domestic circuits Z can be taken simply as the resistance R of the conductor.
Tables of current carrying capacities and volt drops are given in the 16th Edition of the Wiring Regulations which can be obtained from most libraries.
2007-01-23 07:25:03 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The formula has to include current. Cables usually have a resistance value quoted as ohms per metre. Use this to find the overall resistance.
Then the formula is ohm's law. V=I*R where voltage drop is the resistance times the current.
2007-01-22 01:33:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋
If you know the voltage and the resistance of the cable which is often given as ohms per 100metre length you then apply the formula I amps x R resistance = Voltage drop.
2007-01-22 01:46:44 · answer #4 · answered by ANF 7 · 0⤊ 0⤋
Volt drop is calculated with the formula
(mV*A*m)/1000
Where "mV" is a figure given by cable suppliers or obtained from BS7671 (IEE Wiring Regulations).
“A” is the design current i.e. current absorbed by the circuit (not the mcb rating)
“m” is the length of the cable in meters.
2007-01-22 02:16:57 · answer #5 · answered by Yeuris C 1 · 0⤊ 0⤋
da formulation is going like this:--- V=(i*p*l)/a, i=present day, p=density, l=length, a=go-section section............ or if we dont have the density then merely divide the cost of voltage by skill of the entire length of cord and then multiply it by skill of the needed length of cord.
2016-11-26 01:53:58 · answer #6 · answered by Anonymous · 0⤊ 0⤋
use V=IR etc
this page is very useful
http://www.powerstream.com/Wire_Size.htm
2007-01-23 09:42:20 · answer #7 · answered by sir_krippen 2 · 0⤊ 0⤋