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2007-01-21 07:34:19 · 7 answers · asked by s_s_hussey 1 in Science & Mathematics Botany

7 answers

monocot... vascular bundles scattered in stem, leaf veins form a parallel pattern (as with grasses), flower parts in 3's and multiples of 3's
dicots.. vascular bundles in a distinct ring, leaf veins form a net pattern, flower parts in 4's and 5's and multiples of 4 & 5

2007-01-21 07:59:21 · answer #1 · answered by trehugr4life 3 · 1 0

It is a monocot. Take a look at the veins in the leaves. They are all parallel to one another, meaning they look like this |||||||||

Another indication is the number of flower parts is in a multiple of 3. It is a bit difficult with a Calla Lily as the petals are fused.

Lasty, when it begins to sprout from the bulb, you will see only one leaf arising at a time.

Those are the easiest ways to tell. The other way would have you cutting open the stem or sectioning a leaf.

Hope this helps!

2007-01-21 08:50:12 · answer #2 · answered by mtnflower43 4 · 1 0

Calla lilies aren't lilies. They're in Araceae--they have a spathe and spadix (meaning, a spike of tiny little flowers and a colored/white modified bract.) Lilies have large flowers, no bracts, no spikes.

But the other stuff is right. Monocots are "herbaceous" and dicots are "woody." Like, y'know, a tree or shrub. With growth rings and all that.

2007-01-21 09:28:50 · answer #3 · answered by SlowClap 6 · 1 1

Its a monocot. I think the actual taxon of monocots is called liliopsida, refering to the lillies. It has fibrous roots, 3 flower parts, parallel veinations on the leaf and unordered vascular bundles.

2007-01-21 08:32:51 · answer #4 · answered by An Agent of Chaos 5 · 0 0

It's a monocot.

PS, there are lots of herbaceous dicots (beans, tobacco, tomato, squash, peppers, etc....)

2007-01-22 04:49:53 · answer #5 · answered by floundering penguins 5 · 0 0

all lilies are monocots

2007-01-21 16:06:50 · answer #6 · answered by mornington observer 2 · 0 0

MONOCOT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2014-09-25 15:31:34 · answer #7 · answered by Simcha 1 · 1 0

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