Can a big battery connected to a series of capacitors and connected to an electric motor run cheaper than gas?

Question

If I get power from a battery and utilize the aid of a series of capacitors and use it to run an electric motor will the cost for maintaining the battery(recharging) be cheaper than utilizing electric current, gas or diesel? Will aligning the capacitors in series not affect the performance of the motor and what are the possible problems that may arise if I use it for a maximum of ten hours? How long will the battery last and the capacitors? What is the limit of force of the correct set set up? Can this be considered as an energy saving concept?

Answer 1

capacitors and motors do only make sense in an AC circuit for keeping the voltage/current phaseshift aligned.

In a DC circuit it will not come to my mind how a capacitor shall save any energy, hence charging them will cost you nearly the same ammount of energy as using the charge as a power source.

If you find a way loading the capacitors without the battery ..let's say for a car .. using energy from breaking for example, then the capacitors may help to reduce energy consumption while starting the motor again.

Answer 2

Series-connected capacitors will not pass DC current. How can using electrical current be cheaper than using electrical current?

Answer 3

almost no tool is right. it incredibly is seen for functional objective that no cutting-edge passes via a capacitor, in spite of if it is definitely the suitable state of capacitor. initially some cutting-edge bypass via it for sometime(theoretically for countless time). in spite of if in theoretical examine we evaluate each and every gadget to be suitable, so a capacitor shouldn't supply any resistance to cutting-edge via it. yet without resistance, cutting-edge would be countless via circuit. putting a resistor provides the thank you to define preliminary cutting-edge and likewise purposes in offering a differential equation b/w can charge/ cutting-edge/skill and Time in circuit and subsequently it turns into much less complicated to foretell project of a circuit at a given instant. In very final state, no cutting-edge flows in circuit, for this reason no skill is developed for the time of resistor. So presence or absence of a resistor has theoretically no result on maximum can charge saved in capacitor.