2007-01-20 05:41:18 · 4 answers · asked by Expression 5 in Science & Mathematics ➔ Engineering
Divide the stone into :1,27,9,3. Now by adding sometimes and subtracting other times you can weigh at one time weights 1 to 40 inclusive! By the way if you decrease 27 by one each time until you reach 1,1,9,3 you can cut stones into 4 parts such that the stone weights vary between 14 and 40 in units of weight by increments of one. Actually the problem is solved generally as a geometric progression with base 3 and number of terms equal the number of pieces. The sum of the geometric series is the total weight of the stone. In this case S=(x^n-1)/x-1. here x=3, n=4, and S=40.
All problems of this kind are solved in this manner with the same equation! Try it!
2007-01-21 20:25:59 · answer #1 · answered by Mesab123 6 · 0⤊ 0⤋
Let W1, W2, W3, and W4 be the weights where each Wi is such that 1
2007-01-20 13:53:24
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answer #2
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answered by 1ofSelby's 6
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If 1
1
finally 1
Based on the force act on the stone it can be divided into 4 parts. based on the size its wt varies.
2007-01-21 00:46:06 · answer #3 · answered by prasanna k 2 · 0⤊ 0⤋
1,3,7,29
2007-01-20 13:49:53 · answer #4 · answered by wizardno.1989 2 · 0⤊ 0⤋