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4 answers

Well, sin(2A) = 2sin(A)cos(A)

So, sin(2t)cos(2t) = 1/2 (2sin(2t)cos(2t)]
= 1/2{sin(2*2t))]
= 1/2 sin(4t)

L{sin(2t)cos(2t)} = L{1/2sin(4t)}
=1/2 L{sin(4t)}
=1/2[4/ (s^2 + 4^2)]
=1/2[4/(s^2 + 16)]
= 2/(s^2 + 16)

Shook off a little rust on that one.

2007-01-19 13:48:35 · answer #1 · answered by SAN 5 · 1 0

if i know how to solve this laplace question , i might have answered in my exams and passed there.....

lol......

2007-01-20 09:18:15 · answer #2 · answered by Life ♥♥♥ 2 · 0 0

L(t) = dirac delta(do your own freaking homework)

2007-01-19 21:40:11 · answer #3 · answered by Anonymous · 0 0

This is Diffeq not engineering

2007-01-19 23:52:10 · answer #4 · answered by Scott S 4 · 0 1

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