I have a motor (3ph) that the rpm is 1725, my gear box has a ratio of 10:1, what is my speed on the shaft atached to this gear box and what is the formula?....thanks for your input.
2007-01-19 09:59:46 · 3 answers · asked by hector596 2 in Science & Mathematics ➔ Engineering
I think that this is really simple. First, the fact that there's no mention of a load i.e. any force/torque required makes the power rating ("3hp") irrelevant. I assume that the 10:1 ratio means that the gear box is gearing it down (not up) by a factor of 10. Thus, to get the rotational speed of the shaft you just divide the motor's rotational speed (1725 rpm) by 10. So the answer is 172.5 rpm.
2007-01-19 10:24:30 · answer #1 · answered by pollux 4 · 1⤊ 0⤋
if this is a reduction box it will reduce to 172.5 revolution per minute=if your trying to increase speed by this factor i would have to c the unit
2007-01-19 20:31:39 · answer #2 · answered by bev 5 · 0⤊ 0⤋
machine parts design usually needs belts type
this was long time now
2007-01-19 21:56:53 · answer #3 · answered by Eyad E 3 · 0⤊ 0⤋