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A force F acting at a point A displaces a body to a point B.

The coordinates of A are (-3,17,-15)
The coordinates of B are (16,4,15)
The force is given by F=22i +22j 2+2k

2007-01-18 05:57:58 · 5 answers · asked by ozi 1 in Science & Mathematics Engineering

5 answers

I would think that the equation W = F*d where d is distance would work. In that case I would use the vector magnitudes.
d = sqrt((16+3)^2+(4-17)^2+(15+15)^2) = 37.815
F = sqrt(22^2+22^2+22^2) = 38.105
Assuming that the 22j2+2k is supposed to be 22j+22k the W would be 1440.94.

2007-01-18 06:25:10 · answer #1 · answered by uahgrad05 3 · 0 0

This is done using the equation
work = force * distance

force (F) = (22,22,22)

distance (D) = B - A = (19, -13, 30)

then take the scalar product of force and distance

work done = (22*19) + (22*(-13)) + (22* 30)
work done = 418 - 286 + 660
work done = 792

if the force is in newtons and the distance is in metres then the units would be joules

2007-01-18 14:44:55 · answer #2 · answered by Mike 5 · 0 0

vector AB = b - a = (19, -13, 30) = 19i - 13j + 30k
Force = 22i + 22j + 22k
Work done = (22i + 22j + 22k ) . (19i - 13j + 30k)
joules
= 22 (i + j + k) . (19i - 13j + 30k) joules
=22(19 -13 + 30) joules = 22 x 36 joules= 792 joules

2007-01-19 14:18:46 · answer #3 · answered by Como 7 · 0 0

Look up the definition of (Mechanical) Work in Wiki (see below).

When you understand the definition you will be able to calculate the answer yourself.

To calculate distance from co-ordinates, look up in Wiki for 'distance' (the formula you need is 2nd para in Geometry)

2007-01-22 11:19:50 · answer #4 · answered by Steve B 7 · 0 0

W=a*m* IdI

2007-01-18 14:45:55 · answer #5 · answered by JAMES 4 · 0 0

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